3.8 Exercises

3-1

Let FF be a field of characteristic 0. Show that F(X2)F(X2X)=FF(X^{2})\cap F(X^{2}-X)=F (intersection inside F(X)F(X)). [Hint: Find automorphisms σ\sigma and τ\tau of F(X)F(X), each of order 22, fixing F(X2)F(X^{2}) and F(X2X)F(X^{2}-X) respectively, and show that στ\sigma\tau has infinite order.]

3-2
44 4 This problem shows that every quadratic extension of {\mathbb{Q}} is contained in a cyclotomic extension of {\mathbb{Q}}. The Kronecker-Weber theorem says that every abelian extension of {\mathbb{Q}} is contained in a cyclotomic extension.

Let pp be an odd prime, and let ζ\zeta be a primitive ppth root of 11 in \mathbb{C}. Let E=[ζ]E={\mathbb{Q}}[\zeta], and let G=Gal(E/)G=\operatorname{Gal}(E/{\mathbb{Q}}); thus G=(/(p))×G=(\mathbb{Z}/(p))^{\times}. Let HH be the subgroup of index 22 in GG. Put α=iHζi\alpha=\sum_{i\in H}\zeta^{i} and β=iGHζi\beta=\sum_{i\in G\setminus H}\zeta^{i}. Show:

  1. (a)

    α\alpha and β\beta are fixed by HH;

  2. (b)

    if σGH\sigma\in G\setminus H, then σα=β\sigma\alpha=\beta, σβ=α\sigma\beta=\alpha.

Thus α\alpha and β\beta are roots of the polynomial X2+X+αβ[X]X^{2}+X+\alpha\beta\in{\mathbb{Q}}[X]. Compute55 5 Schoof suggests computing αβ\alpha-\beta instead. αβ\alpha\beta and show that the fixed field of HH is [p]{\mathbb{Q}}[\sqrt{p}] when p1mod4p\equiv 1\,\mod 4 and [p]{\mathbb{Q}}[\sqrt{-p}] when p3mod4p\equiv 3\mod 4.

3-3

Let M=[2,3]M={\mathbb{Q}}[\sqrt{2},\sqrt{3}] and E=M[(2+2)(3+3)]E=M[\sqrt{(\sqrt{2}+2)(\sqrt{3}+3)}] (subfields of \mathbb{R}).

  1. (a)

    Show that MM is Galois over {\mathbb{Q}} with Galois group the 44-group C2×C2C_{2}\times C_{2}.

  2. (b)

    Show that EE is Galois over {\mathbb{Q}} with Galois group the quaternion group.

3-4

Let EE be a Galois extension of FF with Galois group GG, and let LL be the fixed field of a subgroup HH of GG. Show that the automomorphism group of L/FL/F is N/HN/H where NN is the normalizer of HH in GG.

3-5

Let EE be a finite extension of FF. Show that the order of Aut(E/F)\operatorname{Aut}(E/F) divides the degree [E:F].[E\colon F].