1.8 The subfield generated by a subset

An intersection of subfields of a field is again a field. Let FF be a subfield of a field EE, and let SS be a subset of EE. The intersection of all the subfields of EE containing FF and SS is obviously the smallest subfield of EE containing both FF and SS. We call it the subfield of EE generated by FF and SS (or generated over FF by SS), and we denote it F(S)F(S). It is the field of fractions of F[S]F[S] in EE because this is a subfield of EE containing FF and SS and contained in every other such field. When S={α1,,αn}S=\{\alpha_{1},...,\alpha_{n}\}, we write F(α1,,αn)F(\alpha_{1},...,\alpha_{n}) for F(S)F(S). Thus, F[α1,,αn]F[\alpha_{1},\ldots,\alpha_{n}] consists of all elements of EE that can be expressed as polynomials in the αi\alpha_{i} with coefficients in FF, and F(α1,,αn)F(\alpha_{1},\ldots,\alpha_{n}) consists of all elements of EE that can be expressed as a quotient of two such polynomials.

Lemma 1.23 shows that F[S]F[S] is already a field if it is finite-dimensional over FF, in which case F(S)=F[S]F(S)=F[S].

Example 1.24

(a) The field (π)\mathbb{Q}(\pi), π=3.14\pi=3.14\ldots, consists of the complex numbers that can be expressed as a quotient

g(π)/h(π),g(X),h(X)[X],h(X)0.g(\pi)/h(\pi),\quad g(X),h(X)\in\mathbb{Q}[X],\quad h(X)\neq 0.

(b) The ring [i]\mathbb{Q}[i] is already a field.

An extension EE of FF is said to be simple if E=F(α)E=F(\alpha) some αE\alpha\in E. For example, (π)\mathbb{Q}(\pi) and [i]\mathbb{Q}[i] are simple extensions of .\mathbb{Q}.

Let FF and FF^{\prime} be subfields of a field EE. The intersection of the subfields of EE containing both FF and FF^{\prime} is obviously the smallest subfield of EE containing both FF and FF^{\prime}. We call it the composite of FF and FF^{\prime} in EE, and we denote it by FFF\cdot F^{\prime}. It can also be described as the subfield of EE generated over FF by FF^{\prime}, or the subfield generated over FF^{\prime} by FF:

F(F)=FF=F(F).F(F^{\prime})=F\cdot F^{\prime}=F^{\prime}(F)\text{.}